Integrand size = 43, antiderivative size = 453 \[ \int \frac {\cos ^2(c+d x) \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right )}{(a+b \cos (c+d x))^{5/2}} \, dx=\frac {2 \left (8 a^4 b B-15 a^2 b^3 B+3 b^5 B-2 a^3 b^2 (A-14 C)+2 a b^4 (3 A-4 C)-16 a^5 C\right ) \sqrt {a+b \cos (c+d x)} E\left (\frac {1}{2} (c+d x)|\frac {2 b}{a+b}\right )}{3 b^4 \left (a^2-b^2\right )^2 d \sqrt {\frac {a+b \cos (c+d x)}{a+b}}}-\frac {2 \left (8 a^3 b B-9 a b^3 B-2 a^2 b^2 (A-8 C)-16 a^4 C+b^4 (3 A+C)\right ) \sqrt {\frac {a+b \cos (c+d x)}{a+b}} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),\frac {2 b}{a+b}\right )}{3 b^4 \left (a^2-b^2\right ) d \sqrt {a+b \cos (c+d x)}}-\frac {2 \left (A b^2-a (b B-a C)\right ) \cos ^2(c+d x) \sin (c+d x)}{3 b \left (a^2-b^2\right ) d (a+b \cos (c+d x))^{3/2}}-\frac {2 a \left (4 A b^4+a \left (3 a^2 b B-7 b^3 B-6 a^3 C+10 a b^2 C\right )\right ) \sin (c+d x)}{3 b^3 \left (a^2-b^2\right )^2 d \sqrt {a+b \cos (c+d x)}}+\frac {2 \left (A b^2-a b B+2 a^2 C-b^2 C\right ) \sqrt {a+b \cos (c+d x)} \sin (c+d x)}{3 b^3 \left (a^2-b^2\right ) d} \]
-2/3*(A*b^2-a*(B*b-C*a))*cos(d*x+c)^2*sin(d*x+c)/b/(a^2-b^2)/d/(a+b*cos(d* x+c))^(3/2)-2/3*a*(4*A*b^4+a*(3*B*a^2*b-7*B*b^3-6*C*a^3+10*C*a*b^2))*sin(d *x+c)/b^3/(a^2-b^2)^2/d/(a+b*cos(d*x+c))^(1/2)+2/3*(A*b^2-B*a*b+2*C*a^2-C* b^2)*sin(d*x+c)*(a+b*cos(d*x+c))^(1/2)/b^3/(a^2-b^2)/d+2/3*(8*B*a^4*b-15*B *a^2*b^3+3*B*b^5-2*a^3*b^2*(A-14*C)+2*a*b^4*(3*A-4*C)-16*C*a^5)*(cos(1/2*d *x+1/2*c)^2)^(1/2)/cos(1/2*d*x+1/2*c)*EllipticE(sin(1/2*d*x+1/2*c),2^(1/2) *(b/(a+b))^(1/2))*(a+b*cos(d*x+c))^(1/2)/b^4/(a^2-b^2)^2/d/((a+b*cos(d*x+c ))/(a+b))^(1/2)-2/3*(8*B*a^3*b-9*B*a*b^3-2*a^2*b^2*(A-8*C)-16*a^4*C+b^4*(3 *A+C))*(cos(1/2*d*x+1/2*c)^2)^(1/2)/cos(1/2*d*x+1/2*c)*EllipticF(sin(1/2*d *x+1/2*c),2^(1/2)*(b/(a+b))^(1/2))*((a+b*cos(d*x+c))/(a+b))^(1/2)/b^4/(a^2 -b^2)/d/(a+b*cos(d*x+c))^(1/2)
Time = 5.25 (sec) , antiderivative size = 377, normalized size of antiderivative = 0.83 \[ \int \frac {\cos ^2(c+d x) \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right )}{(a+b \cos (c+d x))^{5/2}} \, dx=\frac {2 \left (\frac {\left (\frac {a+b \cos (c+d x)}{a+b}\right )^{3/2} \left (b^2 \left (2 a^3 b B-6 a b^3 B-4 a^4 C+b^4 (3 A+C)+a^2 b^2 (A+7 C)\right ) \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),\frac {2 b}{a+b}\right )-\left (-8 a^4 b B+15 a^2 b^3 B-3 b^5 B+2 a^3 b^2 (A-14 C)+16 a^5 C+2 a b^4 (-3 A+4 C)\right ) \left ((a+b) E\left (\frac {1}{2} (c+d x)|\frac {2 b}{a+b}\right )-a \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),\frac {2 b}{a+b}\right )\right )\right )}{(a-b)^2 (a+b)}+\frac {b \left (2 a^4 A b^2-10 a^2 A b^4-8 a^5 b B+16 a^3 b^3 B+16 a^6 C-25 a^4 b^2 C+b^6 C+2 a b \left (-5 a^3 b B+9 a b^3 B+2 a^2 b^2 (A-8 C)+10 a^4 C+2 b^4 (-3 A+C)\right ) \cos (c+d x)+\left (-a^2 b+b^3\right )^2 C \cos (2 (c+d x))\right ) \sin (c+d x)}{2 \left (a^2-b^2\right )^2}\right )}{3 b^4 d (a+b \cos (c+d x))^{3/2}} \]
Integrate[(Cos[c + d*x]^2*(A + B*Cos[c + d*x] + C*Cos[c + d*x]^2))/(a + b* Cos[c + d*x])^(5/2),x]
(2*((((a + b*Cos[c + d*x])/(a + b))^(3/2)*(b^2*(2*a^3*b*B - 6*a*b^3*B - 4* a^4*C + b^4*(3*A + C) + a^2*b^2*(A + 7*C))*EllipticF[(c + d*x)/2, (2*b)/(a + b)] - (-8*a^4*b*B + 15*a^2*b^3*B - 3*b^5*B + 2*a^3*b^2*(A - 14*C) + 16* a^5*C + 2*a*b^4*(-3*A + 4*C))*((a + b)*EllipticE[(c + d*x)/2, (2*b)/(a + b )] - a*EllipticF[(c + d*x)/2, (2*b)/(a + b)])))/((a - b)^2*(a + b)) + (b*( 2*a^4*A*b^2 - 10*a^2*A*b^4 - 8*a^5*b*B + 16*a^3*b^3*B + 16*a^6*C - 25*a^4* b^2*C + b^6*C + 2*a*b*(-5*a^3*b*B + 9*a*b^3*B + 2*a^2*b^2*(A - 8*C) + 10*a ^4*C + 2*b^4*(-3*A + C))*Cos[c + d*x] + (-(a^2*b) + b^3)^2*C*Cos[2*(c + d* x)])*Sin[c + d*x])/(2*(a^2 - b^2)^2)))/(3*b^4*d*(a + b*Cos[c + d*x])^(3/2) )
Time = 2.59 (sec) , antiderivative size = 462, normalized size of antiderivative = 1.02, number of steps used = 18, number of rules used = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.419, Rules used = {3042, 3526, 27, 3042, 3510, 27, 3042, 3502, 27, 3042, 3231, 3042, 3134, 3042, 3132, 3142, 3042, 3140}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\cos ^2(c+d x) \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right )}{(a+b \cos (c+d x))^{5/2}} \, dx\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \int \frac {\sin \left (c+d x+\frac {\pi }{2}\right )^2 \left (A+B \sin \left (c+d x+\frac {\pi }{2}\right )+C \sin \left (c+d x+\frac {\pi }{2}\right )^2\right )}{\left (a+b \sin \left (c+d x+\frac {\pi }{2}\right )\right )^{5/2}}dx\) |
\(\Big \downarrow \) 3526 |
\(\displaystyle -\frac {2 \int \frac {\cos (c+d x) \left (-3 \left (2 C a^2-b B a+A b^2-b^2 C\right ) \cos ^2(c+d x)+3 b (b B-a (A+C)) \cos (c+d x)+4 \left (A b^2-a (b B-a C)\right )\right )}{2 (a+b \cos (c+d x))^{3/2}}dx}{3 b \left (a^2-b^2\right )}-\frac {2 \sin (c+d x) \cos ^2(c+d x) \left (A b^2-a (b B-a C)\right )}{3 b d \left (a^2-b^2\right ) (a+b \cos (c+d x))^{3/2}}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle -\frac {\int \frac {\cos (c+d x) \left (-3 \left (2 C a^2-b B a+A b^2-b^2 C\right ) \cos ^2(c+d x)+3 b (b B-a (A+C)) \cos (c+d x)+4 \left (A b^2-a (b B-a C)\right )\right )}{(a+b \cos (c+d x))^{3/2}}dx}{3 b \left (a^2-b^2\right )}-\frac {2 \sin (c+d x) \cos ^2(c+d x) \left (A b^2-a (b B-a C)\right )}{3 b d \left (a^2-b^2\right ) (a+b \cos (c+d x))^{3/2}}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle -\frac {\int \frac {\sin \left (c+d x+\frac {\pi }{2}\right ) \left (-3 \left (2 C a^2-b B a+A b^2-b^2 C\right ) \sin \left (c+d x+\frac {\pi }{2}\right )^2+3 b (b B-a (A+C)) \sin \left (c+d x+\frac {\pi }{2}\right )+4 \left (A b^2-a (b B-a C)\right )\right )}{\left (a+b \sin \left (c+d x+\frac {\pi }{2}\right )\right )^{3/2}}dx}{3 b \left (a^2-b^2\right )}-\frac {2 \sin (c+d x) \cos ^2(c+d x) \left (A b^2-a (b B-a C)\right )}{3 b d \left (a^2-b^2\right ) (a+b \cos (c+d x))^{3/2}}\) |
\(\Big \downarrow \) 3510 |
\(\displaystyle -\frac {\frac {2 \int -\frac {3 b \left (a^2-b^2\right ) \left (2 C a^2-b B a+A b^2-b^2 C\right ) \cos ^2(c+d x)+\left (-12 C a^5+6 b B a^4+22 b^2 C a^3-13 b^3 B a^2+2 b^4 (2 A-3 C) a+3 b^5 B\right ) \cos (c+d x)+b \left (4 A b^4+a \left (-6 C a^3+3 b B a^2+10 b^2 C a-7 b^3 B\right )\right )}{2 \sqrt {a+b \cos (c+d x)}}dx}{b^2 \left (a^2-b^2\right )}+\frac {2 a \sin (c+d x) \left (a \left (-6 a^3 C+3 a^2 b B+10 a b^2 C-7 b^3 B\right )+4 A b^4\right )}{b^2 d \left (a^2-b^2\right ) \sqrt {a+b \cos (c+d x)}}}{3 b \left (a^2-b^2\right )}-\frac {2 \sin (c+d x) \cos ^2(c+d x) \left (A b^2-a (b B-a C)\right )}{3 b d \left (a^2-b^2\right ) (a+b \cos (c+d x))^{3/2}}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle -\frac {\frac {2 a \sin (c+d x) \left (a \left (-6 a^3 C+3 a^2 b B+10 a b^2 C-7 b^3 B\right )+4 A b^4\right )}{b^2 d \left (a^2-b^2\right ) \sqrt {a+b \cos (c+d x)}}-\frac {\int \frac {3 b \left (a^2-b^2\right ) \left (2 C a^2-b B a+A b^2-b^2 C\right ) \cos ^2(c+d x)+\left (-12 C a^5+6 b B a^4+22 b^2 C a^3-13 b^3 B a^2+2 b^4 (2 A-3 C) a+3 b^5 B\right ) \cos (c+d x)+b \left (4 A b^4+a \left (-6 C a^3+3 b B a^2+10 b^2 C a-7 b^3 B\right )\right )}{\sqrt {a+b \cos (c+d x)}}dx}{b^2 \left (a^2-b^2\right )}}{3 b \left (a^2-b^2\right )}-\frac {2 \sin (c+d x) \cos ^2(c+d x) \left (A b^2-a (b B-a C)\right )}{3 b d \left (a^2-b^2\right ) (a+b \cos (c+d x))^{3/2}}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle -\frac {\frac {2 a \sin (c+d x) \left (a \left (-6 a^3 C+3 a^2 b B+10 a b^2 C-7 b^3 B\right )+4 A b^4\right )}{b^2 d \left (a^2-b^2\right ) \sqrt {a+b \cos (c+d x)}}-\frac {\int \frac {3 b \left (a^2-b^2\right ) \left (2 C a^2-b B a+A b^2-b^2 C\right ) \sin \left (c+d x+\frac {\pi }{2}\right )^2+\left (-12 C a^5+6 b B a^4+22 b^2 C a^3-13 b^3 B a^2+2 b^4 (2 A-3 C) a+3 b^5 B\right ) \sin \left (c+d x+\frac {\pi }{2}\right )+b \left (4 A b^4+a \left (-6 C a^3+3 b B a^2+10 b^2 C a-7 b^3 B\right )\right )}{\sqrt {a+b \sin \left (c+d x+\frac {\pi }{2}\right )}}dx}{b^2 \left (a^2-b^2\right )}}{3 b \left (a^2-b^2\right )}-\frac {2 \sin (c+d x) \cos ^2(c+d x) \left (A b^2-a (b B-a C)\right )}{3 b d \left (a^2-b^2\right ) (a+b \cos (c+d x))^{3/2}}\) |
\(\Big \downarrow \) 3502 |
\(\displaystyle -\frac {\frac {2 a \sin (c+d x) \left (a \left (-6 a^3 C+3 a^2 b B+10 a b^2 C-7 b^3 B\right )+4 A b^4\right )}{b^2 d \left (a^2-b^2\right ) \sqrt {a+b \cos (c+d x)}}-\frac {\frac {2 \int \frac {3 \left (\left (-4 C a^4+2 b B a^3+b^2 (A+7 C) a^2-6 b^3 B a+b^4 (3 A+C)\right ) b^2+\left (-16 C a^5+8 b B a^4-2 b^2 (A-14 C) a^3-15 b^3 B a^2+2 b^4 (3 A-4 C) a+3 b^5 B\right ) \cos (c+d x) b\right )}{2 \sqrt {a+b \cos (c+d x)}}dx}{3 b}+\frac {2 \left (a^2-b^2\right ) \sin (c+d x) \left (2 a^2 C-a b B+A b^2-b^2 C\right ) \sqrt {a+b \cos (c+d x)}}{d}}{b^2 \left (a^2-b^2\right )}}{3 b \left (a^2-b^2\right )}-\frac {2 \sin (c+d x) \cos ^2(c+d x) \left (A b^2-a (b B-a C)\right )}{3 b d \left (a^2-b^2\right ) (a+b \cos (c+d x))^{3/2}}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle -\frac {\frac {2 a \sin (c+d x) \left (a \left (-6 a^3 C+3 a^2 b B+10 a b^2 C-7 b^3 B\right )+4 A b^4\right )}{b^2 d \left (a^2-b^2\right ) \sqrt {a+b \cos (c+d x)}}-\frac {\frac {\int \frac {\left (-4 C a^4+2 b B a^3+b^2 (A+7 C) a^2-6 b^3 B a+b^4 (3 A+C)\right ) b^2+\left (-16 C a^5+8 b B a^4-2 b^2 (A-14 C) a^3-15 b^3 B a^2+2 b^4 (3 A-4 C) a+3 b^5 B\right ) \cos (c+d x) b}{\sqrt {a+b \cos (c+d x)}}dx}{b}+\frac {2 \left (a^2-b^2\right ) \sin (c+d x) \left (2 a^2 C-a b B+A b^2-b^2 C\right ) \sqrt {a+b \cos (c+d x)}}{d}}{b^2 \left (a^2-b^2\right )}}{3 b \left (a^2-b^2\right )}-\frac {2 \sin (c+d x) \cos ^2(c+d x) \left (A b^2-a (b B-a C)\right )}{3 b d \left (a^2-b^2\right ) (a+b \cos (c+d x))^{3/2}}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle -\frac {\frac {2 a \sin (c+d x) \left (a \left (-6 a^3 C+3 a^2 b B+10 a b^2 C-7 b^3 B\right )+4 A b^4\right )}{b^2 d \left (a^2-b^2\right ) \sqrt {a+b \cos (c+d x)}}-\frac {\frac {\int \frac {\left (-4 C a^4+2 b B a^3+b^2 (A+7 C) a^2-6 b^3 B a+b^4 (3 A+C)\right ) b^2+\left (-16 C a^5+8 b B a^4-2 b^2 (A-14 C) a^3-15 b^3 B a^2+2 b^4 (3 A-4 C) a+3 b^5 B\right ) \sin \left (c+d x+\frac {\pi }{2}\right ) b}{\sqrt {a+b \sin \left (c+d x+\frac {\pi }{2}\right )}}dx}{b}+\frac {2 \left (a^2-b^2\right ) \sin (c+d x) \left (2 a^2 C-a b B+A b^2-b^2 C\right ) \sqrt {a+b \cos (c+d x)}}{d}}{b^2 \left (a^2-b^2\right )}}{3 b \left (a^2-b^2\right )}-\frac {2 \sin (c+d x) \cos ^2(c+d x) \left (A b^2-a (b B-a C)\right )}{3 b d \left (a^2-b^2\right ) (a+b \cos (c+d x))^{3/2}}\) |
\(\Big \downarrow \) 3231 |
\(\displaystyle -\frac {\frac {2 a \sin (c+d x) \left (a \left (-6 a^3 C+3 a^2 b B+10 a b^2 C-7 b^3 B\right )+4 A b^4\right )}{b^2 d \left (a^2-b^2\right ) \sqrt {a+b \cos (c+d x)}}-\frac {\frac {\left (-16 a^5 C+8 a^4 b B-2 a^3 b^2 (A-14 C)-15 a^2 b^3 B+2 a b^4 (3 A-4 C)+3 b^5 B\right ) \int \sqrt {a+b \cos (c+d x)}dx-\left (a^2-b^2\right ) \left (-16 a^4 C+8 a^3 b B-2 a^2 b^2 (A-8 C)-9 a b^3 B+b^4 (3 A+C)\right ) \int \frac {1}{\sqrt {a+b \cos (c+d x)}}dx}{b}+\frac {2 \left (a^2-b^2\right ) \sin (c+d x) \left (2 a^2 C-a b B+A b^2-b^2 C\right ) \sqrt {a+b \cos (c+d x)}}{d}}{b^2 \left (a^2-b^2\right )}}{3 b \left (a^2-b^2\right )}-\frac {2 \sin (c+d x) \cos ^2(c+d x) \left (A b^2-a (b B-a C)\right )}{3 b d \left (a^2-b^2\right ) (a+b \cos (c+d x))^{3/2}}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle -\frac {\frac {2 a \sin (c+d x) \left (a \left (-6 a^3 C+3 a^2 b B+10 a b^2 C-7 b^3 B\right )+4 A b^4\right )}{b^2 d \left (a^2-b^2\right ) \sqrt {a+b \cos (c+d x)}}-\frac {\frac {\left (-16 a^5 C+8 a^4 b B-2 a^3 b^2 (A-14 C)-15 a^2 b^3 B+2 a b^4 (3 A-4 C)+3 b^5 B\right ) \int \sqrt {a+b \sin \left (c+d x+\frac {\pi }{2}\right )}dx-\left (a^2-b^2\right ) \left (-16 a^4 C+8 a^3 b B-2 a^2 b^2 (A-8 C)-9 a b^3 B+b^4 (3 A+C)\right ) \int \frac {1}{\sqrt {a+b \sin \left (c+d x+\frac {\pi }{2}\right )}}dx}{b}+\frac {2 \left (a^2-b^2\right ) \sin (c+d x) \left (2 a^2 C-a b B+A b^2-b^2 C\right ) \sqrt {a+b \cos (c+d x)}}{d}}{b^2 \left (a^2-b^2\right )}}{3 b \left (a^2-b^2\right )}-\frac {2 \sin (c+d x) \cos ^2(c+d x) \left (A b^2-a (b B-a C)\right )}{3 b d \left (a^2-b^2\right ) (a+b \cos (c+d x))^{3/2}}\) |
\(\Big \downarrow \) 3134 |
\(\displaystyle -\frac {\frac {2 a \sin (c+d x) \left (a \left (-6 a^3 C+3 a^2 b B+10 a b^2 C-7 b^3 B\right )+4 A b^4\right )}{b^2 d \left (a^2-b^2\right ) \sqrt {a+b \cos (c+d x)}}-\frac {\frac {\frac {\left (-16 a^5 C+8 a^4 b B-2 a^3 b^2 (A-14 C)-15 a^2 b^3 B+2 a b^4 (3 A-4 C)+3 b^5 B\right ) \sqrt {a+b \cos (c+d x)} \int \sqrt {\frac {a}{a+b}+\frac {b \cos (c+d x)}{a+b}}dx}{\sqrt {\frac {a+b \cos (c+d x)}{a+b}}}-\left (a^2-b^2\right ) \left (-16 a^4 C+8 a^3 b B-2 a^2 b^2 (A-8 C)-9 a b^3 B+b^4 (3 A+C)\right ) \int \frac {1}{\sqrt {a+b \sin \left (c+d x+\frac {\pi }{2}\right )}}dx}{b}+\frac {2 \left (a^2-b^2\right ) \sin (c+d x) \left (2 a^2 C-a b B+A b^2-b^2 C\right ) \sqrt {a+b \cos (c+d x)}}{d}}{b^2 \left (a^2-b^2\right )}}{3 b \left (a^2-b^2\right )}-\frac {2 \sin (c+d x) \cos ^2(c+d x) \left (A b^2-a (b B-a C)\right )}{3 b d \left (a^2-b^2\right ) (a+b \cos (c+d x))^{3/2}}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle -\frac {\frac {2 a \sin (c+d x) \left (a \left (-6 a^3 C+3 a^2 b B+10 a b^2 C-7 b^3 B\right )+4 A b^4\right )}{b^2 d \left (a^2-b^2\right ) \sqrt {a+b \cos (c+d x)}}-\frac {\frac {\frac {\left (-16 a^5 C+8 a^4 b B-2 a^3 b^2 (A-14 C)-15 a^2 b^3 B+2 a b^4 (3 A-4 C)+3 b^5 B\right ) \sqrt {a+b \cos (c+d x)} \int \sqrt {\frac {a}{a+b}+\frac {b \sin \left (c+d x+\frac {\pi }{2}\right )}{a+b}}dx}{\sqrt {\frac {a+b \cos (c+d x)}{a+b}}}-\left (a^2-b^2\right ) \left (-16 a^4 C+8 a^3 b B-2 a^2 b^2 (A-8 C)-9 a b^3 B+b^4 (3 A+C)\right ) \int \frac {1}{\sqrt {a+b \sin \left (c+d x+\frac {\pi }{2}\right )}}dx}{b}+\frac {2 \left (a^2-b^2\right ) \sin (c+d x) \left (2 a^2 C-a b B+A b^2-b^2 C\right ) \sqrt {a+b \cos (c+d x)}}{d}}{b^2 \left (a^2-b^2\right )}}{3 b \left (a^2-b^2\right )}-\frac {2 \sin (c+d x) \cos ^2(c+d x) \left (A b^2-a (b B-a C)\right )}{3 b d \left (a^2-b^2\right ) (a+b \cos (c+d x))^{3/2}}\) |
\(\Big \downarrow \) 3132 |
\(\displaystyle -\frac {\frac {2 a \sin (c+d x) \left (a \left (-6 a^3 C+3 a^2 b B+10 a b^2 C-7 b^3 B\right )+4 A b^4\right )}{b^2 d \left (a^2-b^2\right ) \sqrt {a+b \cos (c+d x)}}-\frac {\frac {\frac {2 \left (-16 a^5 C+8 a^4 b B-2 a^3 b^2 (A-14 C)-15 a^2 b^3 B+2 a b^4 (3 A-4 C)+3 b^5 B\right ) \sqrt {a+b \cos (c+d x)} E\left (\frac {1}{2} (c+d x)|\frac {2 b}{a+b}\right )}{d \sqrt {\frac {a+b \cos (c+d x)}{a+b}}}-\left (a^2-b^2\right ) \left (-16 a^4 C+8 a^3 b B-2 a^2 b^2 (A-8 C)-9 a b^3 B+b^4 (3 A+C)\right ) \int \frac {1}{\sqrt {a+b \sin \left (c+d x+\frac {\pi }{2}\right )}}dx}{b}+\frac {2 \left (a^2-b^2\right ) \sin (c+d x) \left (2 a^2 C-a b B+A b^2-b^2 C\right ) \sqrt {a+b \cos (c+d x)}}{d}}{b^2 \left (a^2-b^2\right )}}{3 b \left (a^2-b^2\right )}-\frac {2 \sin (c+d x) \cos ^2(c+d x) \left (A b^2-a (b B-a C)\right )}{3 b d \left (a^2-b^2\right ) (a+b \cos (c+d x))^{3/2}}\) |
\(\Big \downarrow \) 3142 |
\(\displaystyle -\frac {\frac {2 a \sin (c+d x) \left (a \left (-6 a^3 C+3 a^2 b B+10 a b^2 C-7 b^3 B\right )+4 A b^4\right )}{b^2 d \left (a^2-b^2\right ) \sqrt {a+b \cos (c+d x)}}-\frac {\frac {\frac {2 \left (-16 a^5 C+8 a^4 b B-2 a^3 b^2 (A-14 C)-15 a^2 b^3 B+2 a b^4 (3 A-4 C)+3 b^5 B\right ) \sqrt {a+b \cos (c+d x)} E\left (\frac {1}{2} (c+d x)|\frac {2 b}{a+b}\right )}{d \sqrt {\frac {a+b \cos (c+d x)}{a+b}}}-\frac {\left (a^2-b^2\right ) \left (-16 a^4 C+8 a^3 b B-2 a^2 b^2 (A-8 C)-9 a b^3 B+b^4 (3 A+C)\right ) \sqrt {\frac {a+b \cos (c+d x)}{a+b}} \int \frac {1}{\sqrt {\frac {a}{a+b}+\frac {b \cos (c+d x)}{a+b}}}dx}{\sqrt {a+b \cos (c+d x)}}}{b}+\frac {2 \left (a^2-b^2\right ) \sin (c+d x) \left (2 a^2 C-a b B+A b^2-b^2 C\right ) \sqrt {a+b \cos (c+d x)}}{d}}{b^2 \left (a^2-b^2\right )}}{3 b \left (a^2-b^2\right )}-\frac {2 \sin (c+d x) \cos ^2(c+d x) \left (A b^2-a (b B-a C)\right )}{3 b d \left (a^2-b^2\right ) (a+b \cos (c+d x))^{3/2}}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle -\frac {\frac {2 a \sin (c+d x) \left (a \left (-6 a^3 C+3 a^2 b B+10 a b^2 C-7 b^3 B\right )+4 A b^4\right )}{b^2 d \left (a^2-b^2\right ) \sqrt {a+b \cos (c+d x)}}-\frac {\frac {\frac {2 \left (-16 a^5 C+8 a^4 b B-2 a^3 b^2 (A-14 C)-15 a^2 b^3 B+2 a b^4 (3 A-4 C)+3 b^5 B\right ) \sqrt {a+b \cos (c+d x)} E\left (\frac {1}{2} (c+d x)|\frac {2 b}{a+b}\right )}{d \sqrt {\frac {a+b \cos (c+d x)}{a+b}}}-\frac {\left (a^2-b^2\right ) \left (-16 a^4 C+8 a^3 b B-2 a^2 b^2 (A-8 C)-9 a b^3 B+b^4 (3 A+C)\right ) \sqrt {\frac {a+b \cos (c+d x)}{a+b}} \int \frac {1}{\sqrt {\frac {a}{a+b}+\frac {b \sin \left (c+d x+\frac {\pi }{2}\right )}{a+b}}}dx}{\sqrt {a+b \cos (c+d x)}}}{b}+\frac {2 \left (a^2-b^2\right ) \sin (c+d x) \left (2 a^2 C-a b B+A b^2-b^2 C\right ) \sqrt {a+b \cos (c+d x)}}{d}}{b^2 \left (a^2-b^2\right )}}{3 b \left (a^2-b^2\right )}-\frac {2 \sin (c+d x) \cos ^2(c+d x) \left (A b^2-a (b B-a C)\right )}{3 b d \left (a^2-b^2\right ) (a+b \cos (c+d x))^{3/2}}\) |
\(\Big \downarrow \) 3140 |
\(\displaystyle -\frac {2 \sin (c+d x) \cos ^2(c+d x) \left (A b^2-a (b B-a C)\right )}{3 b d \left (a^2-b^2\right ) (a+b \cos (c+d x))^{3/2}}-\frac {\frac {2 a \sin (c+d x) \left (a \left (-6 a^3 C+3 a^2 b B+10 a b^2 C-7 b^3 B\right )+4 A b^4\right )}{b^2 d \left (a^2-b^2\right ) \sqrt {a+b \cos (c+d x)}}-\frac {\frac {2 \left (a^2-b^2\right ) \sin (c+d x) \left (2 a^2 C-a b B+A b^2-b^2 C\right ) \sqrt {a+b \cos (c+d x)}}{d}+\frac {\frac {2 \left (-16 a^5 C+8 a^4 b B-2 a^3 b^2 (A-14 C)-15 a^2 b^3 B+2 a b^4 (3 A-4 C)+3 b^5 B\right ) \sqrt {a+b \cos (c+d x)} E\left (\frac {1}{2} (c+d x)|\frac {2 b}{a+b}\right )}{d \sqrt {\frac {a+b \cos (c+d x)}{a+b}}}-\frac {2 \left (a^2-b^2\right ) \left (-16 a^4 C+8 a^3 b B-2 a^2 b^2 (A-8 C)-9 a b^3 B+b^4 (3 A+C)\right ) \sqrt {\frac {a+b \cos (c+d x)}{a+b}} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),\frac {2 b}{a+b}\right )}{d \sqrt {a+b \cos (c+d x)}}}{b}}{b^2 \left (a^2-b^2\right )}}{3 b \left (a^2-b^2\right )}\) |
(-2*(A*b^2 - a*(b*B - a*C))*Cos[c + d*x]^2*Sin[c + d*x])/(3*b*(a^2 - b^2)* d*(a + b*Cos[c + d*x])^(3/2)) - ((2*a*(4*A*b^4 + a*(3*a^2*b*B - 7*b^3*B - 6*a^3*C + 10*a*b^2*C))*Sin[c + d*x])/(b^2*(a^2 - b^2)*d*Sqrt[a + b*Cos[c + d*x]]) - (((2*(8*a^4*b*B - 15*a^2*b^3*B + 3*b^5*B - 2*a^3*b^2*(A - 14*C) + 2*a*b^4*(3*A - 4*C) - 16*a^5*C)*Sqrt[a + b*Cos[c + d*x]]*EllipticE[(c + d*x)/2, (2*b)/(a + b)])/(d*Sqrt[(a + b*Cos[c + d*x])/(a + b)]) - (2*(a^2 - b^2)*(8*a^3*b*B - 9*a*b^3*B - 2*a^2*b^2*(A - 8*C) - 16*a^4*C + b^4*(3*A + C))*Sqrt[(a + b*Cos[c + d*x])/(a + b)]*EllipticF[(c + d*x)/2, (2*b)/(a + b)])/(d*Sqrt[a + b*Cos[c + d*x]]))/b + (2*(a^2 - b^2)*(A*b^2 - a*b*B + 2*a ^2*C - b^2*C)*Sqrt[a + b*Cos[c + d*x]]*Sin[c + d*x])/d)/(b^2*(a^2 - b^2))) /(3*b*(a^2 - b^2))
3.11.54.3.1 Defintions of rubi rules used
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[2*(Sqrt[a + b]/d)*EllipticE[(1/2)*(c - Pi/2 + d*x), 2*(b/(a + b))], x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 - b^2, 0] && GtQ[a + b, 0]
Int[Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[Sqrt[a + b*Sin[c + d*x]]/Sqrt[(a + b*Sin[c + d*x])/(a + b)] Int[Sqrt[a/(a + b) + ( b/(a + b))*Sin[c + d*x]], x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 - b^2 , 0] && !GtQ[a + b, 0]
Int[1/Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2/(d*S qrt[a + b]))*EllipticF[(1/2)*(c - Pi/2 + d*x), 2*(b/(a + b))], x] /; FreeQ[ {a, b, c, d}, x] && NeQ[a^2 - b^2, 0] && GtQ[a + b, 0]
Int[1/Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[Sqrt[(a + b*Sin[c + d*x])/(a + b)]/Sqrt[a + b*Sin[c + d*x]] Int[1/Sqrt[a/(a + b) + (b/(a + b))*Sin[c + d*x]], x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 - b^2, 0] && !GtQ[a + b, 0]
Int[((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])/Sqrt[(a_) + (b_.)*sin[(e_.) + ( f_.)*(x_)]], x_Symbol] :> Simp[(b*c - a*d)/b Int[1/Sqrt[a + b*Sin[e + f*x ]], x], x] + Simp[d/b Int[Sqrt[a + b*Sin[e + f*x]], x], x] /; FreeQ[{a, b , c, d, e, f}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0]
Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)] + (C_.)*sin[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> Simp[(-C)*Co s[e + f*x]*((a + b*Sin[e + f*x])^(m + 1)/(b*f*(m + 2))), x] + Simp[1/(b*(m + 2)) Int[(a + b*Sin[e + f*x])^m*Simp[A*b*(m + 2) + b*C*(m + 1) + (b*B*(m + 2) - a*C)*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, e, f, A, B, C, m}, x] && !LtQ[m, -1]
Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])*((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)] + (C_.)*sin[(e_.) + (f _.)*(x_)]^2), x_Symbol] :> Simp[(-(b*c - a*d))*(A*b^2 - a*b*B + a^2*C)*Cos[ e + f*x]*((a + b*Sin[e + f*x])^(m + 1)/(b^2*f*(m + 1)*(a^2 - b^2))), x] - S imp[1/(b^2*(m + 1)*(a^2 - b^2)) Int[(a + b*Sin[e + f*x])^(m + 1)*Simp[b*( m + 1)*((b*B - a*C)*(b*c - a*d) - A*b*(a*c - b*d)) + (b*B*(a^2*d + b^2*d*(m + 1) - a*b*c*(m + 2)) + (b*c - a*d)*(A*b^2*(m + 2) + C*(a^2 + b^2*(m + 1)) ))*Sin[e + f*x] - b*C*d*(m + 1)*(a^2 - b^2)*Sin[e + f*x]^2, x], x], x] /; F reeQ[{a, b, c, d, e, f, A, B, C}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0] && LtQ[m, -1]
Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_)*((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)] + (C_.)*sin[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> Simp[(-(c^2*C - B*c*d + A*d^2))*Cos[e + f*x ]*(a + b*Sin[e + f*x])^m*((c + d*Sin[e + f*x])^(n + 1)/(d*f*(n + 1)*(c^2 - d^2))), x] + Simp[1/(d*(n + 1)*(c^2 - d^2)) Int[(a + b*Sin[e + f*x])^(m - 1)*(c + d*Sin[e + f*x])^(n + 1)*Simp[A*d*(b*d*m + a*c*(n + 1)) + (c*C - B* d)*(b*c*m + a*d*(n + 1)) - (d*(A*(a*d*(n + 2) - b*c*(n + 1)) + B*(b*d*(n + 1) - a*c*(n + 2))) - C*(b*c*d*(n + 1) - a*(c^2 + d^2*(n + 1))))*Sin[e + f*x ] + b*(d*(B*c - A*d)*(m + n + 2) - C*(c^2*(m + 1) + d^2*(n + 1)))*Sin[e + f *x]^2, x], x], x] /; FreeQ[{a, b, c, d, e, f, A, B, C}, x] && NeQ[b*c - a*d , 0] && NeQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] && GtQ[m, 0] && LtQ[n, -1]
Leaf count of result is larger than twice the leaf count of optimal. \(1501\) vs. \(2(487)=974\).
Time = 14.54 (sec) , antiderivative size = 1502, normalized size of antiderivative = 3.32
method | result | size |
default | \(\text {Expression too large to display}\) | \(1502\) |
parts | \(\text {Expression too large to display}\) | \(3058\) |
int(cos(d*x+c)^2*(A+B*cos(d*x+c)+C*cos(d*x+c)^2)/(a+b*cos(d*x+c))^(5/2),x, method=_RETURNVERBOSE)
-(-(-2*cos(1/2*d*x+1/2*c)^2*b-a+b)*sin(1/2*d*x+1/2*c)^2)^(1/2)*(2*a^2*(A*b ^2-B*a*b+C*a^2)/b^4*(1/6/b/(a-b)/(a+b)*cos(1/2*d*x+1/2*c)*(-2*b*sin(1/2*d* x+1/2*c)^4+(a+b)*sin(1/2*d*x+1/2*c)^2)^(1/2)/(cos(1/2*d*x+1/2*c)^2+1/2/b*( a-b))^2+8/3*b*sin(1/2*d*x+1/2*c)^2/(a-b)^2/(a+b)^2*cos(1/2*d*x+1/2*c)*a/(- (-2*cos(1/2*d*x+1/2*c)^2*b-a+b)*sin(1/2*d*x+1/2*c)^2)^(1/2)+(3*a-b)/(3*a^3 +3*a^2*b-3*a*b^2-3*b^3)*(sin(1/2*d*x+1/2*c)^2)^(1/2)*((2*cos(1/2*d*x+1/2*c )^2*b+a-b)/(a-b))^(1/2)/(-2*b*sin(1/2*d*x+1/2*c)^4+(a+b)*sin(1/2*d*x+1/2*c )^2)^(1/2)*EllipticF(cos(1/2*d*x+1/2*c),(-2*b/(a-b))^(1/2))-4/3*a/(a-b)/(a +b)^2*(sin(1/2*d*x+1/2*c)^2)^(1/2)*((2*cos(1/2*d*x+1/2*c)^2*b+a-b)/(a-b))^ (1/2)/(-2*b*sin(1/2*d*x+1/2*c)^4+(a+b)*sin(1/2*d*x+1/2*c)^2)^(1/2)*(Ellipt icF(cos(1/2*d*x+1/2*c),(-2*b/(a-b))^(1/2))-EllipticE(cos(1/2*d*x+1/2*c),(- 2*b/(a-b))^(1/2))))+2*a/b^4*(2*A*b^2-3*B*a*b+4*C*a^2)/sin(1/2*d*x+1/2*c)^2 /(2*b*sin(1/2*d*x+1/2*c)^2-a-b)/(a^2-b^2)*(-2*b*sin(1/2*d*x+1/2*c)^4+(a+b) *sin(1/2*d*x+1/2*c)^2)^(1/2)*(2*b*sin(1/2*d*x+1/2*c)^2*cos(1/2*d*x+1/2*c)+ (sin(1/2*d*x+1/2*c)^2)^(1/2)*(-2*b/(a-b)*sin(1/2*d*x+1/2*c)^2+(a+b)/(a-b)) ^(1/2)*EllipticE(cos(1/2*d*x+1/2*c),(-2*b/(a-b))^(1/2))*a-(sin(1/2*d*x+1/2 *c)^2)^(1/2)*(-2*b/(a-b)*sin(1/2*d*x+1/2*c)^2+(a+b)/(a-b))^(1/2)*b*Ellipti cE(cos(1/2*d*x+1/2*c),(-2*b/(a-b))^(1/2)))+2/3/b^4/(-2*b*sin(1/2*d*x+1/2*c )^4+(a+b)*sin(1/2*d*x+1/2*c)^2)^(1/2)*(4*C*b^2*cos(1/2*d*x+1/2*c)*sin(1/2* d*x+1/2*c)^4+3*A*b^2*(sin(1/2*d*x+1/2*c)^2)^(1/2)*(-2*b/(a-b)*sin(1/2*d...
Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.27 (sec) , antiderivative size = 1512, normalized size of antiderivative = 3.34 \[ \int \frac {\cos ^2(c+d x) \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right )}{(a+b \cos (c+d x))^{5/2}} \, dx=\text {Too large to display} \]
integrate(cos(d*x+c)^2*(A+B*cos(d*x+c)+C*cos(d*x+c)^2)/(a+b*cos(d*x+c))^(5 /2),x, algorithm="fricas")
1/9*(6*(8*C*a^6*b^2 - 4*B*a^5*b^3 + (A - 13*C)*a^4*b^4 + 8*B*a^3*b^5 - (5* A - C)*a^2*b^6 + (C*a^4*b^4 - 2*C*a^2*b^6 + C*b^8)*cos(d*x + c)^2 + (10*C* a^5*b^3 - 5*B*a^4*b^4 + 2*(A - 8*C)*a^3*b^5 + 9*B*a^2*b^6 - 2*(3*A - C)*a* b^7)*cos(d*x + c))*sqrt(b*cos(d*x + c) + a)*sin(d*x + c) + (sqrt(2)*(-32*I *C*a^6*b^2 + 16*I*B*a^5*b^3 - 4*I*(A - 17*C)*a^4*b^4 - 36*I*B*a^3*b^5 + I* (9*A - 37*C)*a^2*b^6 + 24*I*B*a*b^7 - 3*I*(3*A + C)*b^8)*cos(d*x + c)^2 - 2*sqrt(2)*(32*I*C*a^7*b - 16*I*B*a^6*b^2 + 4*I*(A - 17*C)*a^5*b^3 + 36*I*B *a^4*b^4 - I*(9*A - 37*C)*a^3*b^5 - 24*I*B*a^2*b^6 + 3*I*(3*A + C)*a*b^7)* cos(d*x + c) + sqrt(2)*(-32*I*C*a^8 + 16*I*B*a^7*b - 4*I*(A - 17*C)*a^6*b^ 2 - 36*I*B*a^5*b^3 + I*(9*A - 37*C)*a^4*b^4 + 24*I*B*a^3*b^5 - 3*I*(3*A + C)*a^2*b^6))*sqrt(b)*weierstrassPInverse(4/3*(4*a^2 - 3*b^2)/b^2, -8/27*(8 *a^3 - 9*a*b^2)/b^3, 1/3*(3*b*cos(d*x + c) + 3*I*b*sin(d*x + c) + 2*a)/b) + (sqrt(2)*(32*I*C*a^6*b^2 - 16*I*B*a^5*b^3 + 4*I*(A - 17*C)*a^4*b^4 + 36* I*B*a^3*b^5 - I*(9*A - 37*C)*a^2*b^6 - 24*I*B*a*b^7 + 3*I*(3*A + C)*b^8)*c os(d*x + c)^2 - 2*sqrt(2)*(-32*I*C*a^7*b + 16*I*B*a^6*b^2 - 4*I*(A - 17*C) *a^5*b^3 - 36*I*B*a^4*b^4 + I*(9*A - 37*C)*a^3*b^5 + 24*I*B*a^2*b^6 - 3*I* (3*A + C)*a*b^7)*cos(d*x + c) + sqrt(2)*(32*I*C*a^8 - 16*I*B*a^7*b + 4*I*( A - 17*C)*a^6*b^2 + 36*I*B*a^5*b^3 - I*(9*A - 37*C)*a^4*b^4 - 24*I*B*a^3*b ^5 + 3*I*(3*A + C)*a^2*b^6))*sqrt(b)*weierstrassPInverse(4/3*(4*a^2 - 3*b^ 2)/b^2, -8/27*(8*a^3 - 9*a*b^2)/b^3, 1/3*(3*b*cos(d*x + c) - 3*I*b*sin(...
Timed out. \[ \int \frac {\cos ^2(c+d x) \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right )}{(a+b \cos (c+d x))^{5/2}} \, dx=\text {Timed out} \]
\[ \int \frac {\cos ^2(c+d x) \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right )}{(a+b \cos (c+d x))^{5/2}} \, dx=\int { \frac {{\left (C \cos \left (d x + c\right )^{2} + B \cos \left (d x + c\right ) + A\right )} \cos \left (d x + c\right )^{2}}{{\left (b \cos \left (d x + c\right ) + a\right )}^{\frac {5}{2}}} \,d x } \]
integrate(cos(d*x+c)^2*(A+B*cos(d*x+c)+C*cos(d*x+c)^2)/(a+b*cos(d*x+c))^(5 /2),x, algorithm="maxima")
integrate((C*cos(d*x + c)^2 + B*cos(d*x + c) + A)*cos(d*x + c)^2/(b*cos(d* x + c) + a)^(5/2), x)
\[ \int \frac {\cos ^2(c+d x) \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right )}{(a+b \cos (c+d x))^{5/2}} \, dx=\int { \frac {{\left (C \cos \left (d x + c\right )^{2} + B \cos \left (d x + c\right ) + A\right )} \cos \left (d x + c\right )^{2}}{{\left (b \cos \left (d x + c\right ) + a\right )}^{\frac {5}{2}}} \,d x } \]
integrate(cos(d*x+c)^2*(A+B*cos(d*x+c)+C*cos(d*x+c)^2)/(a+b*cos(d*x+c))^(5 /2),x, algorithm="giac")
integrate((C*cos(d*x + c)^2 + B*cos(d*x + c) + A)*cos(d*x + c)^2/(b*cos(d* x + c) + a)^(5/2), x)
Timed out. \[ \int \frac {\cos ^2(c+d x) \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right )}{(a+b \cos (c+d x))^{5/2}} \, dx=\int \frac {{\cos \left (c+d\,x\right )}^2\,\left (C\,{\cos \left (c+d\,x\right )}^2+B\,\cos \left (c+d\,x\right )+A\right )}{{\left (a+b\,\cos \left (c+d\,x\right )\right )}^{5/2}} \,d x \]